A small finance problem for this morning: I have 100$
to invest for four years. At 2% compound interest, I am
ending up with 108.24$ at maturity.
I want to do better, and go for a 10$ return in the same period.
What should my new interest rate be. My unknown is the log base,
and whatever that is, to the fourth power, yields a multiplier of 1.1
for my investment (of 100$).
log(base(x))1.1 = 4
ln(1.1)/4=0.0238...
My new interest rate is 2.3827
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