Wednesday, July 31, 2024

Math Moment

Asked Meta how tgis gives probability 1:


To show that the given expression has a total probability of 1, we need to calculate the sum of the probabilities of each state. In quantum computing, the probability of a state is given by the square of the absolute value of its coefficient.
Let's break down the expression:
(1+i)/2 |0> + 1/√2 |1>
We have two states:
|0> with coefficient (1+i)/2
|1> with coefficient 1/√2
To calculate the probability of each state, we take the square of the absolute value of its coefficient:
State |0>
Probability = |(1+i)/2|^2
= ((1+i)/2) * ((1-i)/2) (multiplying by complex conjugate)
= (1 - i^2)/4
= (1 + 1)/4
= 2/4
= 1/2
State |1>
Probability = |1/√2|^2
= (1/√2) * (1/√2)
= 1/2
Now, let's add the probabilities of both states:
Total Probability = Probability of |0> + Probability of |1>
= 1/2 + 1/2
= 1
Therefore, the total probability of the given expression is indeed 1.
Note: The i in the coefficient of |0> is the imaginary unit, which satisfies i^2 = -1.


 

Tuesday, July 30, 2024

Point of Fact

 A number of religious groups have protested the mocking of 

The Last Supper in the Paris Olympics, In point of fact, the reference

was not to Leonardo's mural, but to a Dutch painting some 150 years later.



« Le Festin des dieux » (vers 1635-1640), de Jan Harmensz van Bijlert. Dionysos est représenté allongé au premier plan, pressant une grappe de raisin au-dessus de sa bouche. 

Orthogonal

 You

Quantum Computing; what is The Cauchy–Schwarz inequality.

Copilot

The Cauchy–Schwarz inequality, also known as the Cauchy–Bunyakovsky–Schwarz inequality, is a fundamental result in mathematics. It provides an upper bound on the inner product between two vectors in an inner product space based on the product of their vector norms. Let’s break it down:

Statement of the Inequality: For any vectors u and v in an inner product space, the Cauchy–Schwarz inequality states: [ |⟨u, v⟩| ≤ ‖u‖ ‖v‖ ] Here:

(⟨u, v⟩) represents the inner product (also known as the dot product) of vectors u and v.

‖u‖ and ‖v‖ denote the norms (lengths) of vectors u and v, respectively.

Interpretation:

The inequality ensures that the probability of any outcome (when dealing with quantum states) lies between 0 and 1.

Geometrically, it bounds the angle between two vectors in an inner product space.

Equality:

The two sides of the inequality are equal if and only if vectors u and v are linearly dependent (i.e., one is a scalar multiple of the other).

Remember, the Cauchy–Schwarz inequality plays a crucial role in various mathematical contexts, including quantum mechanics and optimization problems. 🌟

                                                              *     *     *

You

Explain to me about the two sides of the equation being equal

Copilot

Certainly! Let’s dive into why the two sides of the Cauchy–Schwarz inequality can be equal.

Equality Condition:

The Cauchy–Schwarz inequality states that for any vectors u and v, the inner product (dot product) satisfies: [ |⟨u, v⟩| ≤ ‖u‖ ‖v‖ ]

The equality condition occurs when vectors u and v are linearly dependent. This means that one vector is a scalar multiple of the other.

Mathematically, if there exists a nonzero scalar (λ) such that (v = λu), then the equality holds: [ |⟨u, v⟩| = ‖u‖ ‖v‖ ]

Geometric Interpretation:

Geometrically, the dot product (⟨u, v⟩) represents the projection of vector v onto vector u (or vice versa).

When vectors are linearly dependent, they lie on the same line (or are collinear). In this case, the projection of one vector onto the other is the entire vector itself.

Thus, the dot product magnitude equals the product of their norms.

Example:

Consider two vectors: u and v.

If (v = 3u), they are linearly dependent.

Then:

(⟨u, v⟩ = ‖u‖ ‖v‖)

The angle between them is 0°.

In summary, equality occurs when vectors are aligned or parallel, resulting in the maximum possible dot product. 🌟

                                                         *     *     * 

You

How is this useful in quantum computing

Copilot

The Cauchy–Schwarz inequality has several applications in quantum computing:

Quantum State Bounds:

In quantum mechanics, states are represented by vectors in a Hilbert space.

The Cauchy–Schwarz inequality provides an upper bound on the probability of measuring one quantum state when it is projected onto another state.

For example, if we have two quantum states represented by vectors |ψ⟩ and |φ⟩, the probability of measuring |ψ⟩ when projected onto |φ⟩ satisfies: [ |⟨ψ, φ⟩|^2 ≤ ‖ψ‖^2 ‖φ‖^2 ]

This bound ensures that probabilities remain valid (between 0 and 1).

Quantum Algorithms:

Quantum algorithms often involve manipulating quantum states using unitary transformations.

The Cauchy–Schwarz inequality helps analyze the fidelity of quantum gates and operations.

It ensures that the inner product of transformed states remains within bounds, preserving quantum coherence.

Entanglement and Bell Inequalities:

Entangled quantum states violate classical Bell inequalities.

The Cauchy–Schwarz inequality plays a role in proving these violations.

It helps establish correlations between entangled particles that cannot be explained classically.

Quantum Error Correction:

In quantum error correction codes, stabilizer generators are orthogonal.

The Cauchy–Schwarz inequality ensures that these generators remain linearly independent.

This property is crucial for detecting and correcting errors in quantum codes.

In summary, the Cauchy–Schwarz inequality underpins fundamental aspects of quantum mechanics, ensuring consistency and enabling quantum algorithms and protocols. 🌟

                                                                                   *     *     *

You

Mathematics; does a 2-d vector space have an orthonormal basis, and what is it

Copilot

Certainly! In a two-dimensional vector space, we can indeed find an orthonormal basis. Let’s explore this concept:

Orthonormal Basis:

An orthonormal basis consists of vectors that are both orthogonal (perpendicular to each other) and normalized (of unit length).

Specifically, for a set of vectors ({v_1, v_2}), we require:

(v_1) and (v_2) to be mutually perpendicular (i.e., (\langle v_1, v_2 \rangle = 0)).

The length of each vector to be 1 (i.e., (\langle v_i, v_i \rangle = 1) for (i = 1, 2)).

Example in 2D:

Consider the standard basis vectors in (\mathbb{R}^2):

(e_1 = (1, 0)) (corresponding to the x-axis)

(e_2 = (0, 1)) (corresponding to the y-axis)

These vectors are orthogonal ((\langle e_1, e_2 \rangle = 0)) and have unit length.

Therefore, ({e_1, e_2}) forms an orthonormal basis for (\mathbb{R}^2).

Generalization:

Every finite-dimensional inner product space has an orthonormal basis.

We can obtain it from an arbitrary basis using the Gram–Schmidt process.

In functional analysis, orthonormal bases can also be defined in infinite-dimensional inner product spaces.

In summary, a 2D vector space does indeed have an orthonormal basis, and the standard basis vectors serve as an example. 🌟

                                                          *     *     *

You

What happens in a 3-d vector space

Copilot

In three-dimensional space, we extend the concept of vectors from two dimensions to three. Here’s what you need to know:

Three-Dimensional Coordinate System:

In three dimensions, we use a rectangular coordinate system with three perpendicular axes:

x-axis: Horizontal (left-right).

y-axis: Vertical (up-down).

z-axis: Perpendicular to both x and y axes.

This system is often denoted as ℝ³ (real three-dimensional space).

3D Vectors:

A 3D vector is represented by three coordinates: (x), (y), and (z).

It can be visualized as an arrow in 3D space, connecting an initial point (usually the origin) to a terminal point.

Notation: (\vec{v} = (x, y, z)).

Orthonormal Basis:

Just like in 2D, we can find an orthonormal basis in 3D.

The standard basis vectors are:

(\vec{e}_1 = (1, 0, 0)) (along the x-axis).

(\vec{e}_2 = (0, 1, 0)) (along the y-axis).

(\vec{e}_3 = (0, 0, 1)) (along the z-axis).

These vectors are orthogonal (perpendicular) and have unit length.

In summary, 3D vectors allow us to describe points, lines, and planes in three-dimensional space. 🌟

                                                      *     *     *

You

Am I correct in thinking that the Bloch sphere is a 3-d space with orthogonality expressed differently

Copilot

Indeed, your intuition is on point! The Bloch sphere is a geometric representation of quantum states in a three-dimensional space, and it provides an elegant way to visualize qubit states. Let’s explore this further:

Bloch Sphere Overview:

The Bloch sphere is a unit sphere (radius 1) centered at the origin.

It represents the state space of a single qubit.

Each point on the sphere corresponds to a unique quantum state.

Mapping to 3D Space:

The Bloch sphere maps the complex vector space of qubits (which is inherently higher-dimensional) onto a 3D space.

The three Cartesian coordinates (x, y, z) of a point on the sphere correspond to the coefficients of the qubit state vector.

Orthogonality and Basis Vectors:

The Bloch sphere naturally incorporates orthogonality:

The north pole represents the |0⟩ state (orthogonal to the equator).

The south pole represents the |1⟩ state (also orthogonal to the equator).

The equator itself represents superpositions of |0⟩ and |1⟩ states.

Expressing Quantum States:

Any qubit state |ψ⟩ can be expressed as: [ |ψ⟩ = α|0⟩ + β|1⟩ ] where α and β are complex coefficients.

The Bloch sphere allows us to visualize these coefficients geometrically.

In summary, the Bloch sphere provides an intuitive way to understand qubit states, emphasizing orthogonality and the richness of quantum superpositions. 🌟


                                                              *     *     *

INTERFERENCE:

Sorry

 https://www.lemonde.fr/economie/article/2024/07/29/les-travaillistes-britanniques-decouvrent-un-trou-de-22-milliards-de-livres-dans-les-finances-publiques_6261295_3234.html

Sorry to see help with fuel costs for Seniors go...

Monday, July 29, 2024

Tensors

Interesting to see what operations are performed in this circuit:

The identity operator is introduced, to create a tensor product:

For the second column:


A tensor for the whole:



Our circuit:

                                                                 

Interestingly, one ends up with a negative for the |11> option unless oneof two variants

are introduced: a controlled z-gate, or a swap;

                                                                  







 

Sunday, July 28, 2024

Sampler

 I'm on Lesson 3 of Basics of Quantum Information with IBM. It deals with circuits

and the Smapler and Estimator modules.

                                                                      



Copilot:


The Sampler primitive in IBM Qiskit is a tool for simulating the behavior of a quantum circuit. It allows you to efficiently estimate the probabilities of obtaining different measurement outcomes for a given quantum circuit.

Here's a breakdown of what it does:

Executes the Circuit: The Sampler takes your quantum circuit as input and runs it. This involves applying the gates and operations defined in the circuit to the qubits.

Calculates Probabilities: It then calculates the probabilities of obtaining each possible measurement outcome for the qubits. This is done using a method called "quasi-distribution" (which essentially involves sampling the circuit and building up a probability distribution).

Returns Results: The Sampler returns a results object that holds this information. You can access the probabilities of specific outcomes using the quasi_dists attribute.

Visualization: You can use the plot_histogram function to visualize the probability distribution of the measurement outcomes. This helps you understand the behavior of your quantum circuit.

Why Use the Sampler?

Efficient Simulation: The Sampler is optimized for simulating quantum circuits, particularly when dealing with large numbers of qubits. This is because it uses efficient algorithms to calculate the probabilities.
Understanding Circuit Behavior: It lets you see how the different gates and operations in your circuit influence the measurement outcomes. This can be crucial for debugging and understanding the functionality of your quantum algorithms.
Example:

python

from qiskit import QuantumCircuit
import aer
from qiskit.visualization import plot_histogram

# Create a simple quantum circuit
circuit = QuantumCircuit(2)
circuit.h(0)
circuit.cx(0, 1)
circuit.measure_all()

# Create a sampler object
sampler = Aer.get_backend('qasm_simulator')

# Run the circuit on the sampler
results = sampler.run(circuit).result()

# Extract the probabilities
statistics = results.quasi_dists[0].binary_probabilities()

# Plot the histogram
plot_histogram(statistics)
This code snippet demonstrates how to use the Sampler to simulate a simple quantum circuit, extract the probabilities of measurement outcomes, and visualize them using a histogram.
                                                           
                                                              *     *     *

statistics = results.quasi_dists[0].binary_probabilities() Can you break down this command for me

Let's break down the command


statistics = results.quasi_dists[0].binary_probabilities()
step-by-step:

results: This variable holds the output of running your quantum circuit on the Sampler. It contains information about the simulation, including the probabilities of different measurement outcomes.

results.quasi_dists: This attribute of the results object gives you access to the quasi-distribution of measurement outcomes. A quasi-distribution is a way to represent the probabilities in a format suitable for classical computers. It's essentially a list of probabilities for each possible measurement outcome.

results.quasi_dists[0]: This selects the first quasi-distribution from the list. Since you likely only have one circuit you're running, you're taking the results of that single circuit.

.binary_probabilities(): This method converts the quasi-distribution into a dictionary that maps each possible binary outcome (e.g., "00", "01", "10", "11") to its probability. Think of this as a way to get the probabilities in a format that's easier to understand and work with.

In summary:

The Sampler simulates your quantum circuit and calculates the probabilities of different measurement outcomes.
results.quasi_dists gives you a list of quasi-distributions, one for each circuit run.
results.quasi_dists[0] selects the first (and likely only) quasi-distribution.
.binary_probabilities() converts the quasi-distribution into a dictionary of probabilities for each binary outcome.
This dictionary, stored in the statistics variable, is ready for you to use for analysis or visualization, such as creating a histogram to see the distribution of measurement probabilities.





Saturday, July 27, 2024

Modulo

 Period finding is a topic in Number Theory. Modulo functions are periodic. 

https://young.physics.ucsc.edu/150/period.pdf

Gemini:

This document provides a fascinating explanation of how period finding can be used to factor integers, a concept crucial to quantum computing and cryptography. Let's break down the example with a = 19 and N = 91.

Understanding the Function:

The function f(x) ≡ a^x (mod N) is at the heart of this method. It essentially describes the pattern of remainders when a is raised to increasing powers and divided by N.

The Example with a = 19:

  1. Period: The document states that for a = 19 and N = 91, the period of the function is r = 12. This means that f(x) = f(x + 12) for all values of x.

  2. Visualizing the Period: Figure 2 in the document illustrates this. You can see the function repeats itself every 12 steps.

  3. The Importance of an Even Period: The method relies on the period r being even. In this example, r = 12 is even, which is a crucial condition for the factorization to work.

  4. Finding Factors: The document explains that since r is even, we can use the following:

    • a^(r/2) + 1 is divisible by one of the factors of N.
    • a^(r/2) - 1 is divisible by the other factor of N.
  5. Calculating Factors:

    • text
      a^(r/2) + 1 = 19^(12/2) + 1 = 19^6 + 1 = 47045881 + 1 = 47045882
    • text
      a^(r/2) - 1 = 19^(12/2) - 1 = 19^6 - 1 = 47045881 - 1 = 47045880

    Using Euclid's algorithm to find the greatest common divisor (GCD) of N = 91 with these two values:

    • GCD(91, 47045882) = 13
    • GCD(91, 47045880) = 7

    We have successfully factored N = 91 into its prime factors, 13 and 7.

Key Points:

  • The method relies on finding the period of a specific function.
  • The period needs to be even for this method to work.
  • The process involves calculating two values based on the period and then using Euclid's algorithm to find the factors.

Let me know if you have any other questions!


Perplexity:


Period finding; The document explains that since r is even, we can use the following: a^(r/2) + 1 is divisible by one of the factors of N. a^(r/2) - 1 is divisible by the other factor of N. ... Can you explain this to me

Answer
Certainly! I'd be happy to explain this concept from the period finding algorithm, which is a key part of Shor's algorithm for integer factorization. Let's break it down step by step:

Background

First, let's establish some context:
  1. We're dealing with a composite number N that we want to factorize.
  2. We've chosen a random number a that is coprime to N.
  3. We've found the period r, which is the smallest positive integer such that a^r ≡ 1 (mod N).
  4. We've discovered that r is even.

The Key Insight

The statement you're asking about is based on a fundamental theorem in number theory. Here's how it works:

The Equation

If r is even, we can write:a^r - 1 ≡ 0 (mod N)We can factor this as:(a^(r/2) + 1)(a^(r/2) - 1) ≡ 0 (mod N)

What This Means

This factorization tells us that the product (a^(r/2) + 1)(a^(r/2) - 1) is divisible by N.

Why This Is Useful

Here's the key insight:
  1. Since N divides this product, and N is composite, it's likely that one factor of N divides (a^(r/2) + 1) and the other factor divides (a^(r/2) - 1).
  2. This means that:
    • gcd(a^(r/2) + 1, N) is likely to be a non-trivial factor of N
    • gcd(a^(r/2) - 1, N) is likely to be the other non-trivial factor of N

An Example

Let's use a simple example to illustrate:
  • Suppose N = 15 (factors are 3 and 5)
  • Choose a = 7
  • We find that r = 4 (because 7^4 ≡ 1 (mod 15))
Now:
  • a^(r/2) = 7^2 = 49 ≡ 4 (mod 15)
  • a^(r/2) + 1 = 4 + 1 = 5
  • a^(r/2) - 1 = 4 - 1 = 3
Indeed, 5 is one factor of 15, and 3 is the other!

Conclusion

This property provides a powerful way to find the factors of N once we know the period r. It's not guaranteed to work every time (which is why Shor's algorithm may need to be run multiple times), but it has a high probability of success, making it a crucial part of the quantum factoring algorithm.