Pushing through on the Riemann paper, brackets are everything when
working with a complex exponent:
The placement of the minus sign with respect to the bracket works
as is the case with any variable
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The (1-s) form does not change the value of the i term, but the sign.
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3 appears to be the only number pushing the i value outside the +- .5irange. Dividing by 2 solves all that.
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