Saturday, August 3, 2019

Why

Riemann zeta zeros are computed from imaginary  - i - values.
Tried to replicate 14.1347... Cannot crack why the polar form
is shown with a negative value.


                                                         
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Actually, I needn't worry about sign changes:

And by sixteen, it's positive again:

The sine function cycles naturally, and larger ln factors speed things up.

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Grapher gives standard zeta results.



It is also possible to do sums of series.


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